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$\sqrt[2]{0.004}$
$\int\left(6e^{8t}\right)\:dt$
$\left(-4x^3y^4\right)^2$
$\int\frac{5}{\sqrt{x^2-4x+9}}xdx$
$\left(-3\right)^2\cdot\left(-3\right)^0$
$z^2-24x=-144$
$\frac{\left(5+2x\right)}{\left(3-4x\right)}<-3$
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