$-2\cdot\left|-5-9\right|+-2$

$\frac{x+4}{x-2}=0$

$\lim_{x\to1}\left(\frac{ln\left(1-x\right)-tan\left(7\right)}{x^2}\right)$

$\left(\frac{2}{3}\:a^3\:b^5\:y^6\right):\left(\frac{1}{3}\:a\:b^2\:\right)$

$\frac{m^4-25m+m^2}{m-3}$

$\lim_{x\to\infty}\left(\frac{2x}{x}\right)$

$\left(2\left(-53\right)+4\right)\left(\left(-53\right)-1\right)-\left(\left(-53\right)+1\right)\left(\left(-53\right)-2\right)-\left(-53\right)^2-2\left(-53\right)+3$