$100\:por\:0,9$
$\frac{d}{dx}xcosy=x^2+y^3$
$\left(8xy\right)^{-\frac{2}{3}}$
$\frac{3x^3}{x^2-3}$
$10<x$
$6xy-3x$
$\frac{1+\frac{sen\:x}{cos\:x}}{1+\frac{cos\:x}{sen\:x}}$
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