$9x^{4}-16x^{2}$
$4\sin^2x-3=0$
$\left(-9\right)-\left(-53\right)$
$\int\left(x+1\right)\left(2x+x^2\right)dx$
$\frac{x-2}{x^{2}-4}+\frac{1}{x+2}=\frac{1}{x-2}$
$x^2-14x+63=0$
$\frac{3x^2-2x-8}{x^2+2}$
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