$\frac{7x-3}{\left(4x-1\right)^3\left(x^2+2\right)^2}$
$tan^{-1}=\frac{7}{9}$
$4-\infty$
$\sqrt[6]{\frac{x^{15}}{y^{13}}.z^{18}}$
$\:y^2-64$
$\frac{dy}{\:dx}=-\frac{x^2+y^2+2x}{2xy}$
$\left(b^3-b^{-3}\right)^2$
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