$x\:-7\:<\:4$
$\left(3x-4y\right)+\left(2x-y\right)y'=0$
$b^2x+b^2y$
$\left(-4x^4+9\right)$
$\sec\left(x\right).\cos\left(x\right).\tan\left(x\right)=1-\cos^2x$
$\int\frac{x^3}{\sqrt[2]{x^2-9}}dx$
$\int\sqrt{28x-x^2}dx$
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