$\left(3x+4\right)\left(2x-4\right)\left(8x^2\right)$
$37+7^2$
$-4x+1=-9x+16$
$-5\left(1\:-\:5k\right)\:-\:4\left(2k+5\right)$
$x^3-4x^2-3x+18$
$\frac{d}{dx}y=\frac{x-2}{y+3}$
$x^5-40x^4$
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