$\left(-4n\:+\:b\right)\:\left(4n\:+\:b\right)\:$
$\left(2x^2y\right)\left(-4xy\right)$
$69=1x+2x$
$\frac{\left(2q\right)^{-8}}{\left(2q\right)^{-12}}$
$60\cdot20$
$\left(x+1\right)\left(3x+1\right)$
$\lim_{x\to\infty}\left(\frac{\ln\left(3\right)^2}{x}\right)$
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