$x+10^3$
$4\:x\:9,1$
$\frac{dx}{dt}=\frac{3}{4}-\frac{3x}{100}$
$5\cdot3-6\cdot2+4\cdot3$
$\left(4xy^2+5wz^2\right)^2$
$3\left(x+y+z\right)+5\left(x+y+z\right)$
$\frac{d}{dx}\left(3x^2+4y^2+2z^2=5\right)$
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