$-38+-17$
$\left(0.01\right)^2$
$\lim_{x\to\infty}\left(\frac{-10x}{x^2-5x}\right)$
$\frac{d}{dx}\:in\sqrt[5]{4-3x^5}$
$27,3\cdot360$
$\int\left(x^2+1\right)\cdot\left(x^3+3x\right)dx$
$-2t^2+5t-2=0$
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