$-3+6i$
$12x+4=28$
$sec^2x=\frac{cot^2x+1}{cot^2x}$
$3-7\cdot4-2$
$x^3-6x^2-25x+150$
$6\left(6\right)\left(-6\right)\left(-6\right)$
$\int\:\frac{x^2+5x+2}{\left(x+1\right)\left(x^2+1\right)}dx$
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