$\frac{\left(x+1\right)\left(x+3\right)}{\left(x+2\right)^2}$

$\arccos\left(\frac{\sqrt{6}+1}{2\sqrt{3}}\right)-\arccos\left(\sqrt{\frac{2}{3}}\right)$

$3x^2+240=0$

$x+5\le x+3$

$\int\frac{x}{\left(x-10\right)^7}dx$

$g\left(x\right)=tan\left(3-4\right)+2$

$\frac{x^4-x^3-x+3}{x^3-2x^2+3x}$