$\left(x+1\right)\left(x+6\right)\left(x+3\right)\left(x+4\right)$
$12\left(3+\:y\right)\:=\:5\left(2y\:+\:8\right)$
$\sqrt{5}-2\sqrt{5}$
$5x+3y-2x+y$
$2x^3-5x^2-3x=0$
$x^2+5x\ge0$
$9a^x+3a^x+8a^x$
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