$\int\left(\frac{1}{\sqrt[5]{x}}+\frac{5}{e^{3x}}\right)dx$
$\int\frac{6x^2+1}{\left(x^2-4\right)^2}dx$
$99-\left(-30\right)$
$\int\:\:senx\left(5e^{cosx}\right)dx$
$\lim_{x\to6}\:\left(y-5\right)\left(y-7\right)$
$a^2+b^2=25$
$\lim_{x\to\infty}\left(\frac{x^2-2x}{-3}\right)$
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