$b\left(2-3x^{2}\right)^{6}$
$\frac{\sqrt{4}}{2}$
$\frac{dy}{dx}=\frac{20x-3}{10x^2-3x}$
$\int\left(24x+4\right)e^{12x^2+4x}dx$
$\int_0^2\left(3x^3-6x^2+1\right)dx$
$x2\:-\:8x\:-\:1008$
$\frac{dx}{dt}+tx^3=-\frac{x}{t}$
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