$x^3+y^3=4$
$\frac{dy}{dt}\:=\:\left(y-1\right)\left(y+1\right)$
$\left(a^mb^2+b^ma^2\right)^2$
$\frac{dc}{dt}=\frac{9-6c\left(t\right)}{400}$
$u\:+\:2u\:=\:18$
$\int_{-2}^1\left(\frac{1}{3}f-2\right)^2df$
$\int\frac{2}{3}r^4\ln\left(r\right)dr$
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