$-0.05+15.22$
$x\left(x-4\right)=221$
$x^2-25=129$
$\int\frac{1}{\left(x^2+2x+1\right)\left(x+3\right)}dx$
$14,7+10,5+2,1$
$\lim_{x\to0}\left(\frac{\left(tan\left(x\right)-x\right)}{\left(sin\left(x\right)-x\right)}\right)$
$\int\ln\left(-x+\frac{1}{2}\right)dx$
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