$6-2-10:5-11$
$10x+10y-20z=60$
$-3\:+2\:\cdot2$
$\int\frac{x-3}{6x^{2}+13x+5}dx$
$\left(5a^2+7\right)\left(7a^2-5\right)$
$12x+4$
$\sqrt{26^2}$
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