$\left(16x^3\:+\:8\right)\left(4x\:+\:2\right)$

$\lim_{x\to\infty}\left(\frac{\ln\left(x^2-1\right)}{\ln\left(x^2+3\right)}\right)$

$\int\frac{5}{\left(x+5\right)\left(x-2\right)\:}dx$

$f\left(x\right)=\frac{1}{3}\cdot\left(\frac{1-x}{x}\right)^3$

$\int x\left(ax+b\right)\cdot\ln\left(x\right)dx$

$-2x\left(2x+3\right)+3x\left(3x+2\right)=x-1$

$4\left(-2x^3+9x^2-5x+4\right)$