$10+x=5$
$x^{12}+10x^6y^2\:+25y^4$
$\frac{216}{2}$
$3\left(6x^2+4\right)^3+432x^2\left(6x^2+4\right)^2$
$4+9-9-2+5-2-5+4$
$\int\left(x^2\sqrt{x}+x^2\sqrt{x}+6\sqrt{x}\right)dx$
$\int6e^{-0.05x}dx$
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