$36x^{2}-25y^{4}=\left(6$
$12 \cdot 3 + 18 : ( - 2 + 8 )$
$\int r^2\left(\frac{r^3}{15}-3\right)^4dr$
$\lim_{x\to2}\left(\frac{x-2}{\sqrt{x+1}-\sqrt{5x}}\right)$
$\left(t+1\right)dt=\frac{1}{y^2}dy$
$\left(5x+y^2\right)^2$
$\frac{1}{3}+x<\frac{5}{3}+2x$
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