$\frac{1}{2}e^{2x}x^3+\frac{1}{4}e^{2x}x^2+\frac{1}{4}e^{2x}x-\frac{13}{8}e^{2x}$

$\lim_{h\to0}\left(\frac{\left(x+h\right)^2+5\left(x+h\right)+3-\left(x^2+5x+3\right)}{h}\right)$

$\left(m^2\right)\cdot\left(-7xy+40y^2\right)$

$4\:x\:-5\:x\:-10$

$cos\left(y-x\right)=cos\left(x-y\right)$

$\sqrt[2]{4y}.\sqrt[4]{8y^3}$

$2x+\sqrt{x+3}=4$