$4x^2+16x=48$
$2x^2+x-5=0$
$x^2-25x+25$
$3x-1=x+3$
$168-252-42$
$y'=\frac{x^2\cdot\:\:y-y}{y^4+y^2+1}$
$\left(2x-8\right)^5$
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