$\left(137x-5x^2-6x^3\right)y$
$-\:12\:\:+\:\:\left(\:-\:28\:\right)\:-\:\:\left(\:-\:17\:\right)\:\:+\:15\:$
$4\cdot3-2y$
$\frac{1}{\cot\left(x\right)}-2\cot\left(x\right)$
$\left(6x^3+1\right)\left(1-6x^3\right)$
$\int9x^8\left(x^9-5\right)dx$
$\frac{dy}{dx}=-\frac{x}{y},\:y\left(1\right)=1$
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