$\int sin^5\left(3x\right)dx$
$\int\left(2y^2+4y\right)^6\left(y+1\right)dy$
$y'=1-x+y-yx$
$-203\:-475$
$12\sin^2\left(t\right)+cos\left(t\right)-6$
$2.645^2$
$\frac{3e\sqrt{5+x}}{1-\sqrt{5-x}}$
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