$\frac{4k\:-\:6}{3k\:-\:9}\:=\:\frac{1}{3}\:$
$\left(2x+1\right)+\left(4x+1\right)\left(2x-3\right)$
$\sec\theta-\frac{\cos\theta}{\sin\theta+1}=\tan\theta$
$2x^2+3x+7=0$
$2\left(-3\right)\left(-6\right)\left(5\right)$
$5x^2+50x+25$
$\frac{1}{4x^3+2x}dy-e^{-y}dx=0$
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