$\left(3x+2y\right)\left(3-2y\right)$
$-1\:+\:-13\:+\:-19\:+\:95\:+\:-24$
$\frac{3x^2+x+2}{x+1}$
$\left(-50\right)-\left(-0\right)$
$\frac{\tan^2\left(x\right)-\sec^2\left(x\right)}{\csc\left(x\right)}$
$\frac{x}{-2}=3$
$\left(-3x^5y^2\right)^4$
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