$b^2+26b+12b$
$a-b=\:c$
$\frac{4\tan\left(x\right)^2}{\left(16+4\tan\left(x\right)^2\right)^{\frac{3}{2}}}$
$\:4x\:-\:4\:-\:8x$
$-4ab^2+8cb^3-16a^2b^4$
$65x^2+75x^3y$
$\frac{d}{dx}\:y^2-4x^5+6xy-6x=6$
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