$\ln\:\left(x^3-2x+1\right)-2\ln\:\left(3x-1\right)$
$2x+10\ge3x-3$
$\frac{\cot\left(x\right)-1}{1+\tan\left(x\right)}$
$x^2-8x+-8$
$\:\frac{x+3}{2}+\frac{x-1}{4}>\:2$
$16j^2k-8j^6k^5+60j^3$
$2\left(-x-3\right)$
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