$2x\left(1+y^2\right)dx-2y\left(1+x^2\right)dy=0$
$\left(3b-2v^2\right)^3$
$2\sqrt{\infty+1}$
$\int_0^{3\pi}\left(\sec\left(x\right)^2\right)dx$
$3y-2+8y+4$
$+2-\left(-4-2\right)-12$
$\frac{3}{4}.\frac{-4}{1}$
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