$\lim_{x\to-9}\left(\frac{x+9}{x^2+81}\right)$
$\lim_{x\to\infty}\left(\frac{-xe^{2-3x}}{3}\right)$
$-r^2+5r-6$
$4\cdot\left(8-5\right)$
$12-34+45$
$x^4+6x^3+11x^2+6x-24$
$4abx^3-8b^2x^2y\sqrt{2bx^2}$
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