$\left(392-24x\right)^2$

$\left(6-\sqrt[3]{\frac{34884}{78364164096}}\right)^{19}$

$\int_1^2\frac{x^2-4x-9x}{x^3-6x^2+9x}dx$

$\left(18+7x\right)\frac{dy}{dx}=\left(-5-7x\right)5secy$

$\lim_{x\to\infty}\left(3x-\sqrt{4x+2}\right)$

$\frac{8}{a^2+25}+\frac{3}{a+5}-\frac{4}{a-5}$

$\int\frac{x^2+2x}{x\left(x^2-1\right)}dx$