$\left(x-4\right)\left(x-1\right)\left(x+2\right)\left(x-3\right)$
$24x=48$
$\frac{dy}{dx}+y\frac{2x}{x^2+4}=x^2-4$
$\left(-2\right)^4+2^4$
$tan^2a\:+cot^2a\:+2\:=\:sec^2\csc\left(a\right)^2$
$3a-6$
$6^{-2}\cdot6^1$
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