$\left(2a^2-3b^3\right)^4$
$\left(6cg^5\right)^5$
$\frac{t^4-16}{t-2}$
$\sqrt[1]{256}$
$x^2-2+6$
$196x^2y^4-225a^8$
$\left(\frac{2}{5y}^4\right)$
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