$\int\frac{x-1}{x^2-4x+5}dx$
$-40\le\frac{2}{5}x+4$
$tcot^2\left(x\right)$
$\lim_{x\to0}\left(\frac{sin\left(x\right)}{1+8x}\right)$
$ln\left(\frac{y'}{y}\right)$
$\frac{5}{2}x+x^8$
$2x-5>-25$
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