$-6-5\left(-1+3y\right)$
$3\left(1+x^2\right)\frac{dy}{dx}=2xy\left(y^3-1\right)$
$x^3\left(x^4-1\right)^2$
$\frac{-3\left(20\right)}{12}$
$4a\:+\:5a\:+\:3a\:+\:2b\:-\:3b\:+\:5c$
$\left(4x+5\right)\left(-44\right)$
$\left(-1.1\cdot10^{-9}\right)\left(4.8\cdot10^5\right)$
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