$\sqrt{64\cdotr^{2}p^{2}q^{2}}$
$60\cdot\frac{2}{5}$
$3x+6x\:+9$
$\left(6p^3-4m^6\right)^2$
$\frac{\left(1+\tan\left(a\right)\:\right)\:^2}{1-\tan\left(a\right)}$
$\frac{dy}{dx}\:=\:x^2y^4$
$y^2-7+49$
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