$-\frac{ln\left(y\right)}{4}=x+c$

$-6\cos^2x+2\cos x+2=3\cos x$

$\cos\left(4x\right)x\cos\left(2x\right)+\sin\left(2x\right)x\sin\left(4x\right)$

$\frac{sin\left(3\theta\:\right)+sin\theta\:}{cos\theta\:-cos\left(3\theta\:\right)}=cot\theta\:$

$-\left(4x-6\right)^2$

$6\:+\:\left(-4+2\right)\:-\:\left(-3-1\right)$

$2sin^2x=3sinx-1$