$\left(7x^2+y^3\right)^2$
$\left(127.50-23.50\right)+3\left(86.50+4\right)$
$\int x^2t^5dx$
$\frac{dx}{dy}=\frac{x^2y^2}{1+x}\:y\left(1\right)=0$
$18+2.\left(5-9\right)-3.\left(10-7\right)$
$\sqrt{x+5}=7-\sqrt{20-x}$
$x^2-\frac{x}{3}+\frac{1}{3}$
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