$\left(x+42\right)^2$
$\frac{1}{3x}\sqrt[3]{27x^6}y^4$
$750+50x>1000$
$\left(2a^3\cdot a^3\cdot4a\right)^2$
$c=\left(\sqrt{8}+\sqrt{5}\right)\left(\sqrt{8}-\sqrt{5}\right)$
$\left(a+x\right)^2\:.\:\left(2a-x\right)$
$-263=-x-45$
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