$\left(\frac{2}{5}b^3\right)+\left(\frac{2}{5}b^3\right)$

$c=\left(\sec\left(x\right)\:+\:2\:\cos\left(x\right)\right)^2\:+\:\left(2\:\sec\left(x\right)\:-\:\cos\left(x\right)\right)^2$

$2\left(x-1\right)>4\left(x-2\right)$

$\frac{6y^4+4y^5-4y^3}{3y^2}$

$\frac{d}{dx}\left(\left(2x+1\right)^4\left(\frac{1}{3x}-2\right)^3\right)$

$\left(-2\right)\cdot\left(-3\right)-\left(-2\right)$

$28^2+45^2$