$\frac{144}{12}$
$\left(3x^3+4x^2+2x+6\right)+\left(5x^3-2x^2+8x+7\right)$
$\frac{-54}{18}$
$\frac{\sin^3a+\sin a.\cos^2\left(a\right)}{\cos\left(a\right)}=\tan\left(a\right)$
$\frac{10x^4+10x^3+10x^2-10x-16}{5x+10}$
$1\cdot9$
$2a+3b+4c\:cuando\:a\:=2,\:b=1,\:c=3$
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