$3x-11<4$
$20\cdot3-3$
$\frac{1}{2}a^2b^3\frac{12}{5}a^2b^3-\frac{16}{23}a^3b$
$12a^5-20a^4+8a^2-16$
$7x^2-3x\:2$
$\left(7x^2+6x+x^3+4\right)\left(x+5\right)$
$210x^2-63x$
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