$\int\left(3x+1\right)\left(x-2\right)dx$

$\sin\left(x\right)\left(\tan\left(x\right)+\cot\left(x\right)\right)=\tan\left(x\right)$

$5\sin^2x\sec\left(x\right)\cot\left(x\right)=1$

$\frac{5x-4}{2}>-2$

$2\:tan^2\:a\:+\:tan\:a=\:0$

$\frac{3x^2-16}{\left(x^2-4x\right)}$

$\frac{\sin\left(a\right)+\tan\left(a\right)}{1+\cos\left(a\right)}=\tan\left(a\right)$