$\lim_{x\to0}\left(\frac{\left(x+1\right)e^{x^2}}{x^2-1}\right)$
$\frac{xy^2}{2}\cdot\frac{6x}{y^2}$
$\left(7x^2y\:+\:9x^5y\right)\left(7x^2y\:-\:9x^5y\right)$
$x^2+3x+1.5$
$4\:.\:3\:\left(-3\right)\:.\:\left(-2\right)$
$k\left(k+1\right)+2\left(k+1\right)$
$49x^2\:-14x\:+\:1$
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