$\frac{d}{dx}\left(\ln\left(x^3y^2\right)=5y+4\right)$

$5\cdot\left[\frac{x^3}{3}\:\right]_{-2}^6$

$3\sin\left(y\right)\cos\left(y\right)=2\sin\left(y\right)$

$\left(-9\right).\left(-6\right):\left(+6\right)$

$2x^4+x^2+1;\:x=10$

$+9-8-7+3-\left\{-4-\left[+4\right]-8\right\}-\left(+4-3\right)$

$\frac{x}{4}-1>5$