$\int\frac{s^2+6s+9}{\left(s-1\right)\left(s-2\right)\left(s+4\right)}dx$
$16x^6-x^2$
$\frac{80}{240.70}$
$\frac{2x^3-3x+5}{x-2}$
$\int\frac{x+2}{x^2\left(x+1\right)^2}dx$
$4x^2+5x-9-2x^2+5x-20$
$x^2+120x+6$
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