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Find the derivative using logarithmic differentiation method $\frac{d}{dx}\left(\left(x-1\right)^{\cos\left(2x\right)}\right)$

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 Solution

 Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

How to find equivalent expressions by combining like terms and using the distributive property

https://www.youtube.com/watch?v=rHNY01R2VSQ

Using Distributive property twice and combining like terms to solve for x

https://www.youtube.com/watch?v=xrFNRBqaqEk

Derivative of x^x^x, Logarithmic Differentiation of Exponential Functions, Calculus Youtube Video

https://www.youtube.com/watch?v=Vhltl9w6QNM

Worked example: Evaluating derivative with implicit differentiation | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=KyYC8XzKsHU

 Function Plot

Plotting: $\left(-2\sin\left(2x\right)\ln\left(x-1\right)+\frac{\cos\left(2x\right)}{x-1}\right)\left(x-1\right)^{\cos\left(2x\right)}$

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7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Combining like terms

Algebraic expressions can be simplified by combining like terms.

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