$4.5\int\left(300+2x\right)^{0.5}\:dx$
$\lim_{x\to\infty}\left(\frac{1}{x^2+3}\right)$
$31mn+91mn$
$3x^2+4y^2+24x-16y+52=0$
$\frac{dy}{dx}=\frac{y^3}{\left(x^2+5x+6\right)}$
$0.00421\cdot1.000$
$\left(3-x-y\right)\left(2x+y+1\right)\left(x-y\right)$
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