$\tan^2x+1=\csc^2x$
$\int\:\:\:\:\:\frac{1}{x^2\left(x+1\right)^2}dx$
$\frac{d}{dx}\left(12U^3-4U\right)\left(2x\right)$
$n^2+6n+5=0$
$\lim_{x\to0}\left(1-\sin\left(\frac{x}{2}\right)\right)$
$\left(4x^4+x^3-2x+3\right)\:\left(x-2\right)$
$\left(m^4+2n\right)^2$
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